Tuesday, June 16, 2020
SAT Video Friday â⬠Zeroing in on the Answer
n = (10^10 x 9^9 x 8^8â⬠¦3^3 + 2^2 + 1^1)^2 How many zeroes does n^2 contain? First off, you need to recognize the pattern: every number has an exponent equal to itself, i.e. 10^10, 8^8 , etc. That means, that the (â⬠¦.) represents 7^7 x 6^6 x 5^5 x 4^4. Now that we can survey the entire series (and I do recommend writing out the remaining numbers), notice is that 10^10 will yield 10 zeroes. The next step, though, is a little trickier. If you pair 5 and 2, you get 10. Therefore, each pair of 5 and 2 will yield a zero. There are five 5ââ¬â¢s, yet only two 2ââ¬â¢s. But notice how both 4^4 and 8^8 contain a bounty of 2ââ¬â¢s (4^4 = 2^8 and 8^8 = 2^24), so we will have more than enough 2ââ¬â¢s to pair with those five 5ââ¬â¢s. So (5 x 2)^5 will yield a total of 5 more zeroes to ââ¬Ënââ¬â¢, giving us a total of 15. Now to the very last part. The question is looking for n^2. You want to make sure not to square 15. See, when you have some number to an exponent and you are looking for the number of zeroes, you want to multiply by 2, since you are doubling the number of zeroes. Therefore, the answer is 30. Now watch all of that explained in video form here: If you have any questions or comments, please leave them for me in the comment box below! ðŸâ¢â
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